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How to change X and Y of popup
Jackie Roos 8 лет назад
в iRidium Script / Interface scripts
•
обновлен Dmitry - support (expert) 8 лет назад •
2
In my script, when I show a particular popup I want to change its position:
IR.Log( 'IR.GetPopup("Room24_AC").Y ' + IR.GetPopup("Room24_AC").Y)
IR.GetPopup("Room24_AC").Y = 115;
IR.Log( 'IR.GetPopup("Room24_AC").Y ' + IR.GetPopup("Room24_AC").Y)
And this shows as you would expect in the log
[27-05-2016 16:34:15.849] INFO IR.GetPopup("Room24_AC").Y 2
[27-05-2016 16:34:15.860] INFO IR.GetPopup("Room24_AC").Y 115However, It does not show in the Emulator as moved, it is still at X = 2
And on hide I want to change it's position back, so it will be in the default position for use elsewhere in the project
IR.Log( 'IR.GetPopup("Room24_AC").Y ' + IR.GetPopup("Room24_AC").Y)
IR.GetPopup("Room24_AC").Y = 2;
IR.Log( 'IR.GetPopup("Room24_AC").Y ' + IR.GetPopup("Room24_AC").Y) However this always gives
[27-05-2016 16:34:26.402] INFO IR.GetPopup("Room24_AC").Y 2
[27-05-2016 16:34:26.413] INFO IR.GetPopup("Room24_AC").Y 2 I expected if the popup's X coordinate was successfully moved, it should be 115 for the first line and 2 for the second line
How can I change the position of a popup in by script (without deleting it and recreating it)
Сервис поддержки клиентов работает на платформе UserEcho
Hello!
Try adding a small delay before changing the coordinate of the element.
For example:
IR.AddListener(IR.EVENT_ITEM_SHOW,IR.GetItem("Popup 1"),function() { IR.Log( 'IR.GetPopup("Popup 1").Y ' + IR.GetPopup("Popup 1").Y) IR.SetTimeout(50, function(){ IR.GetPopup("Popup 1").Y = 115; IR.Log( 'IR.GetPopup("Popup 1").Y ' + IR.GetPopup("Popup 1").Y) }); })